从头再来
Code: #include “stdio.h” main(){ int a[10],*p,i; for(i=0;i<10;i++){ a[i]=2*i; } p=a; for(i=0;i<10;i++){ printf(“%d\n”,*(p+i)); } } 结果如下: Code: 0 2 4 6 8 10 12 14 16 18 Press any key to continue
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